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NEW QUESTION: 1
A potential customer is looking for a way to explore the data to determine why product sales are rising in one region but falling in another.
Which type of analysis in IBM Cognos BI best meets this requirement?
A. Slice-and-dice and trending
B. Analytical reporting and drilling
C. Scenario modeling
D. Statistics and predictive analytics
Answer: A
Explanation:
IBM Analysis Foundational Knowledge slide 8:
On the left we have the majority of employees in an organization, people looking to find fast
answers to business questions. They're asking one more question beyond simple reporting to get
additional insights such aswhy is this customer performing poorly? What analysis has been made?
It's the simplest of analysis we call analytical reporting. It can be summed up in one simple word,
real. We want to reach all these users in Cognos BI with the licenses in consumers, business
authors, and BI professional owners.
The next group has slightly more requirement. They're looking for factors driving performance. The
up and down trend of performance likewhy is the percentage of growth in one company greater
than another? Their job isn't 100% doing analysis, but they certainly want to slice and dice the
data more than the first group. We want to reach these users with more advanced capabilities of
Cognos 8 BI with licenses of advanced business author, BI professional, maybe Cognos analysis
for Microsoft Excel.

NEW QUESTION: 2
Exhibit:

Which type of cloud system is shown in the exhibit?
A. cloud telemetry
B. cloud storage
C. cloud management
D. cloud security
Answer: A

NEW QUESTION: 3



A. CustNo
B. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
C. CustNoWHERE D.CustNo IS NULL
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
I. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
J. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
Answer: E
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

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