ROM2 Detail Explanation & Examcollection ROM2 Vce - ROM2 Exam Details - Cads-Group

  • Exam Number/Code : ROM2
  • Exam Name : Blue Prism Certified ROMTM 2 Professional Exam
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
If you upgrade to ASM 12cR1 and implement Flex ASM, do you need to upgrade all the databases to
12cR1?
A. Yes. All the databases need to be upgraded to 12cR1
B. No. You can run in a mixed 11.2 database instance and a 12cR1 database instance. The 11.2 instance will use the Flex ASM instance of the other server.
C. No. You cannot upgrade your database instance to 12cR1
D. No. You can run in a mixed 11.2 database instance and a 12cR1 database instance, but the 11.2 instance will fail if the local Flex ASM instance is moved to another server
Answer: D

NEW QUESTION: 2
An information security manager is asked to provide evidence that the organization is fulfilling its legal obligation to protect personal identifiable information (Pll). Which of the f<
A. Written policies and standards
B. Privacy awareness training
C. Metrics related to program effectiveness
D. Risk assessments of privacy-related applications
Answer: C

NEW QUESTION: 3
상사가 데이터 분석을 위해 Amazon Athena를 제공하도록 요청했습니다. 어떻게 이것을 제공해야 합니까?
정답을 선택하십시오.
A. Athena 용 RDS 인스턴스를 생성하면 즉시 데이터 분석을 시작할 수 있습니다. Athena에 데이터를로드 할 필요가 없으며 S3에 저장된 데이터로 직접 작동합니다.
B. Athena에 대한 EC2 인스턴스를 생성하면 즉시 데이터 분석을 시작할 수 있습니다. Athena에 데이터를로드 할 필요가 없으며 S3에 저장된 데이터로 직접 작동합니다.
C. Athena에 데이터를로드합니다. Athena는 서버가 없으므로 설정 또는 관리 할 인프라가 없으므로 즉시 데이터 분석을 시작할 수 있습니다.
D. 아테나는 서버가 없으므로 설정하거나 관리 할 인프라가 없으므로 즉시 데이터 분석을 시작할 수 있습니다. Athena에 데이터를로드 할 필요가 없으며 S3에 저장된 데이터로 직접 작동합니다.
Answer: D
Explanation:
Amazon Athena is an interactive query service that makes it easy to analyze data in Amazon S3 using standard SQL. Athena is serverless, so there is no infrastructure to set up or manage, and you can start analyzing data immediately. You don't even need to load your data into Athena, it works directly with data stored in S3.
Reference:
https://aws.amazon.com/athena/faqs/

NEW QUESTION: 4
Suppose you were told that scores on an examination were converted to standard scores with a mean = 500, range of 800, and a standard deviation of 100. A person with a score of 600 has performed better than what percent of the persons taking the test?
A. 84 percent
B. 97.5 percent
C. 57 percent
Answer: A
Explanation:
Z = (X - MU)/Standard Deviation Z = (600 - 500)/100 = 1 Area between Z and Mean = .3413
Area to Left of Z = .5 + .3413 = .8413 Percentile Rank = 100*.8413 = 84.13 Therefore, the person has performed better than 84 percent of the people.

 

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ROM2 Detail Explanation & Examcollection ROM2 Vce - ROM2 Exam Details - Cads-Group


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