NSE6_FSW-7.2 Test Passing Score - NSE6_FSW-7.2 Cert Guide, Braindump NSE6_FSW-7.2 Pdf - Cads-Group

  • Exam Number/Code : NSE6_FSW-7.2
  • Exam Name : Fortinet NSE 6 - FortiSwitch 7.2
  • Questions and Answers : 260 Q&As
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
Identify the two kernels that are shipped with Oracle Linux 6.
A. Red Hat Compatible Kernel
B. Unbeatable Enterprise Kernel 11g
C. Solaris 11 Container Kernel
D. Linux Compatible Kernel
E. Unbreakable Enterprise Kernel
Answer: A,E
Explanation:
Oracle Linux 6 ships with two sets of kernel packages: *Unbreakable Enterprise Kernel [kernel-uek-2.6.32-100.28.5.el6] Only available on the x86_64 (64 bit) platform Installed and booted by default *Red Hat compatible Kernel [kernel-2.6.32-71.el6] Installed by default
Reference:Oracle Linux 6 Release Notes

NEW QUESTION: 2
質問をドラッグアンドドロップ
IPv4ネットワークサブネットを左側から右側の正しい使用可能なホスト範囲にドラッグアンドドロップします

Answer:
Explanation:

Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111
1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is
172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet.
Therefore the last usable host is 172.28.229.254.

NEW QUESTION: 3
Which of the following would help to ensure the portability of an application connected to a database?
A. Analysis of stored procedures/triggers
B. Verification of database import and export procedures
C. Synchronization of the entity-relation model with the database physical schema
D. Usage of a structured query language (SQL)
Answer: D
Explanation:
The use of SQL facilitates portability. Verification of import and export procedures with other systems ensures better interfacing with other systems, analyzing stored procedures/triggers ensures proper access/performance, and reviewing the design entity-relation model will be helpful, but none of these contribute to the portability of an application connecting to a database.

NEW QUESTION: 4
You create the following JavaScript code:

You have the following requirements:
You must invoke a function that displays the vehicle information within the following HTML element:

<div id="display"></div>
The output of the function must appear on thewebpage as follows:

Vehicle Color is silver
Stay safe!
Vehicle TransmissionType is manual
Big machine!
You need to invoke the JavaScript function to display the required output in the HTML element.
Which two code segments should you use? (Each correct answer presents a complete solution. Choose two.)

A. Option A
B. Option E
C. Option C
D. Option B
E. Option D
Answer: B,C
Explanation:
Explanation/Reference:
The second argument should be 'silver'.
The third argument should be a number less than 4.

 

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