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  • Exam Number/Code : NSE6_FSR-7.3
  • Exam Name : Fortinet NSE 6 - FortiSOAR 7.3 Administrator
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
In the RSTP network as shown in the figure, according to the configuration of the SWC in the figure, it can be determined that the type of the E0/1 port of the SWC is: (Multiple Choice)

A. Edge port
B. Root port
C. Designated port
D. Alternate Port
Answer: A,C

NEW QUESTION: 2
Your company has a primary data center and a secondary data center. The primary data center contains five servers.
The servers are configured as shown in the following table.

You plan to configure Server5 to protect the data from all of the servers on the network.
You need to recommend a backup solution that meets the following requirements:
The data must be available if the primary data center fails.
The solution must retain data for up to two years.
Which two actions should you include in the recommendation? Each answer presents part of the solution.
A. On Server5, back up the data on all of the protected servers to physical disks.
B. Deploy a secondary DPM server to the primary data center and configure the new DPM server to protect Server5.
C. Deploy a secondary DPM server to the secondary data center and configure the new DPM server to protect
Server5.
D. On Server5, back up the data on all of the protected servers to Windows Azure Recovery Services.
E. Deploy a primary DPM server to the secondary data center and configure the new DPM server to protect the
physical disks on Server5.
Answer: C,D

NEW QUESTION: 3


Answer:
Explanation:



NEW QUESTION: 4



A. Option D
B. Option E
C. Option F
D. Option A
E. Option B
F. Option C
Answer: F
Explanation:
let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to 192.168.15.255 So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number of subnets which is 8 and find the exponent of 2 which is 8, that gives you
3 and to find out the summary mask just do /24 - 3 = /21.
if you make it in binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 0000 1000
9 0000 1001
10 0000 1010
11 0000 1011
12 0000 1100
13 0000 1101
14 0000 1110
15 0000 1111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is 192.168.8.0

 

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