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NEW QUESTION: 1
The following code was used when compiling the model:model.compile(optimizer='Adam,loss='categorical.crossentropy',metrics=[tf.keras.metrics.accuracy]), currently using evaluate When the method evaluates the model, which of the following indicators will be output?
A. categorical accuracy
B. loss
C. accuracy
D. categorical_ 1oss
Answer: B,C
NEW QUESTION: 2
You have a web service that is used to pay for food deliveries. The web service uses Azure Cosmos DB as the data store.
You plan to add a new feature that allows users to set a tip amount. The new feature requires that a property named tip on the document in Cosmos DB must be present and contain a numeric value.
There are many existing websites and mobile apps that use the web service that will not be updated to set the tip property for some time.
How should you complete the trigger?
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation:
Box 1: getContext().getRequest();
Box 2: if(isNaN(i)["tip"] ..
In JavaScript, there are two ways to check if a variable is a number :
isNaN() - Stands for "is Not a Number", if variable is not a number, it return true, else return false.
typeof - If variable is a number, it will returns a string named "number".
Box 3:r.setBody(i);
// update the item that will be created
References:
https://docs.microsoft.com/bs-latn-ba/azure/cosmos-db/how-to-write-stored-procedures-triggers-udfs
https://mkyong.com/javascript/check-if-variable-is-a-number-in-javascript/
NEW QUESTION: 3
Quality Chemicals는 판매용 2 가지 등급의 암모니아를 제공합니다. 가격 차이는 있지만, 회사는 저급 화학 제품의 재고가 없을 때마다 고객에게 고급 화학 물질을 제공하고자 합니다. 이런 식으로 그들은 최고의 고객 서비스를 보장합니다.
SAP Business One에서이를 설정하는 가장 좋은 방법은 무엇입니까? 저급 화학 제품의 재고가 없을 때 영업 직원이 고급 품목을 쉽게 찾을 수 있습니까?
정답을 선택하십시오.
응답:
A. 동일한 검색에서 찾을 수 있도록 두 항목을 동일한 항목 그룹에 할당하십시오.
B. 고급 화학 물질을 저급 화학 물질의 대체품으로 만드십시오.
C. 판매 BOM을 생성하여 두 품목을 대체 구성 요소로 연결합니다.
D. 두 화학 항목을 연결하는 할인 그룹을 설정하십시오.
Answer: B
NEW QUESTION: 4
Given:
public class FieldInit { char c; boolean b; float f; void printAll() { System.out.println("c = " + c); System.out.println("c = " + b); System.out.println("c = " + f); }
public static void main(String[] args) { FieldInit f = new FieldInit(); f.printAll();
} }
A. c = null b = false f = 0.0F
B. c = b = false f = 0.0
C. c = null b = true f = 0.0
D. c = 0 b = false f = 0.0f
Answer: B
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Aalk - 2014-05-05 16:45:18
Plato - 2014-05-05 16:45:51
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Eleanore - 2014-09-28 16:36:48