JN0-664 Latest Exam Format & Reliable JN0-664 Mock Test - JN0-664 Test Engine - Cads-Group

  • Exam Number/Code : JN0-664
  • Exam Name : Service Provider, Professional (JNCIP-SP)
  • Questions and Answers : 260 Q&As
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
The system administrator notices that many employees are using passwords that can be easily guessed or
are susceptible to brute force attacks.
Which of the following would BEST mitigate this risk?
A. Shorten the maximum life of account passwords.
B. Increase the minimum password length.
C. Enforce account lockout policies.
D. Enforce password rules requiring complexity.
Answer: D
Explanation:
Section: Access Control and Identity Management
Explanation/Reference:
Explanation:
Password complexity often requires the use of a minimum of three out of four standard character types for
a password. The more characters in a password that includes some character complexity, the more
resistant it is to brute force attacks.

NEW QUESTION: 2
패스트 푸드 식당의 드라이브 스루 서비스는 주문을 시작하기 위해 운전하고, 주문을 지불하기 위해 창으로 진행 한 다음, 주문한 품목을 받기 위해 다른 창으로 진행하는 것으로 구성됩니다. 이 유형의 대기 라인 시스템은 다음과 같습니다.
A. 다중 채널, 다중 위상.
B. 다중 채널, 단상.
C. 단일 채널, 다중 위상.
D. 단일 채널, 단일 위상.
Answer: C
Explanation:
The drive-through represents a single queue (channel). Because this waiting line has three services in series, it may be said to be multiple phase. Another example is the typical factory assembly line. This terminology (channel, phase), however, is not used by all writers on queuing theory.

NEW QUESTION: 3
For the details about managing segmentation models and using the customer segmentation, see the following sections:
Response:
A. Segmenting Customers [page 191]
B. Segmentation Building Blocks [page 217]
C. All of above
D. Segmentation Models [page 190]
Answer: C

NEW QUESTION: 4

A. 6.46
B. 8.6
C. 12.88
D. 6.2
E. 10.74
Answer: E
Explanation:
Antenna performance Antenna performance is measured in dBi (the antennas gain/loss over a theoretical isotropic antenna) dBd (the antennas gain/loss over a dipole antenna) dBi = dBd + 2.15 dBd = dBi - 2.15

 

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