JN0-664 Clearer Explanation & JN0-664 Study Guide Pdf - JN0-664 New Dumps Sheet - Cads-Group

  • Exam Number/Code : JN0-664
  • Exam Name : Service Provider, Professional (JNCIP-SP)
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
Which statement about the OSPF Loop-Free Alternate feature is true?
A. It is supported on routers that are configured with virtual links.
B. It is supported when a traffic engineering tunnel interface is protected.
C. It is supported in VRF OSPF instances.
D. It is supported when traffic can be redirected to a primary neighbor.
Answer: C

NEW QUESTION: 2
会社のセキュリティ計画を設計する必要があります。適切なセキュリティコントロールをフロアプランにドラッグアンドドロップします。
手順:すべてのオブジェクトを使用し、すべてのプレースホルダーを埋める必要があります。順序は関係ありません。シミュレーションが完了したら、[完了]ボタンを選択して送信してください。

Answer:
Explanation:

Explanation:
Cable locks - Adding a cable lock between a laptop and a desk prevents someone from picking it up and walking away Proximity badge + reader Safe is a hardware/physical security measure Mantrap can be used to control access to sensitive areas. CCTV can be used as video surveillance.
Biometric reader can be used to control and prevent unauthorized access. Locking cabinets can be used to protect backup media, documentation and other physical artifacts.

NEW QUESTION: 3
Which statement is true about EMC NetWorker Module for Documentum?
A. It replicates data from any SAN-based array to any other SAN-based array over an existing IP network.
B. It automatically creates and stores server configuration profiles, based on user-defined schedules and retention policies.
C. It performs hot backups of storage areas, database, and Full-text Indexes.
D. It provides object-level recovery of content and metadata.
Answer: C

NEW QUESTION: 4
A customer is investigating replicating data between IBM Storwize V7000 for DR purposes and has made
the following calculations to help determine the correct capacity for the intersite link.
Customer formula used
Amount of data replicated within 24 hours, multiplied by 4 (to allow for peaks and re-sync), translated into
bit rate over the 24-hour period.
Customer calculations
-2GB of data per day
-2GB * 4 =8GB of data
-8GB* 8 bits= 64GB I 86400 seconds
-68,719,476,736 I 86400 = 795,364 bits/second bandwidth
The customer has advised that the working day is 8 hours.
What is the status of the calculations?
A. It is undersized by a factor of 4.
B. It is undersized by a factor of 3.
C. It is correct.
D. It is undersized by a factor of 2.
Answer: B
Explanation:
The calculation is correct for a 24 hour workday, but as the workday is only 8 hours, the calculation is off
by a factor 3.

 

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JN0-664 Clearer Explanation & JN0-664 Study Guide Pdf - JN0-664 New Dumps Sheet - Cads-Group


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