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  • Exam Number/Code : JN0-636
  • Exam Name : Security, Professional (JNCIP-SEC)
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
The process used for documenting user's requirements is known as validation.
A. False
B. True
Answer: A

NEW QUESTION: 2
メディアおよびエンターテインメント企業である雇用主は、世界的に有名ないくつかの有名人のために、ドメインでG SuiteEnterpriseアカウントをプロビジョニングしたいと考えています。リーダーシップは、これらのVIPに高度なプライバシーが提供されるようにすることに関心があります。ドキュメント、チャット、カレンダーなどのG Suiteサービスを使用して、連絡先情報を検索し、VIPとのコラボレーションを開始できるのは、少数のシニア従業員のみです。
これらの要件を満たすように構成する必要があります。あなたは何をするべきか?
A. VIPと正社員用に別々のカスタムディレクトリを作成します。
B. [ディレクトリ設定]で、連絡先の共有を無効にします。
C. ユーザーリストでVIPを見つけ、ユーザー設定「ディレクトリ共有」をオフにします。
D. VIPとそのハンドラーのグループを作成し、[グループアクセスレベル]を[制限付き]に設定します。
Answer: D

NEW QUESTION: 3
You need to display the first names of all customers from the CUSTOMERS table that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?
A. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>'' ANDSUBSTR(cust_first_name, -2, 1)='a';
B. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>0 ANDSUBSTR(cust_first_name, LENGTH(cust_first_name), -2)='a';
C. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>0 ANDSUBSTR(cust_first_name, -2, 1)='a';
D. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')IS NOT NULL ANDSUBSTR(cust_first_name, 1, -2)='a';
Answer: C

 

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