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  • Exam Number/Code : JN0-636
  • Exam Name : Security, Professional (JNCIP-SEC)
  • Questions and Answers : 260 Q&As
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
エンジニアは、ランサムウェア攻撃から自社を保護する必要があります。エンジニアが実行段階をブロックしてファイルの暗号化を防ぐことができるソリューションはどれですか?
A. 侵入ポリシーとSMBの悪用をブロックするsnortルールでCisco Firepowerを使用します。
B. Cisco Firepowerを使用して、TORネットワークへのトラフィックをブロックします。
C. Exploit Preventionエンジンを有効にしてCisco AMP展開を使用します。
D. Malicious Activity Protectionエンジニアを有効にしてCisco AMP展開を使用します。
Answer: D

NEW QUESTION: 2
You deploy Windows 10 to a new computer named Computer1.
You sign in to Computer1 and create a user named User1.
You create a file named LayoutModification.xml in the C:\Users\Default\AppData\Local\Microsoft\Windows\Shell\folder. LayoutModification.xml contains the following markup.

What is the effect of the configuration? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation:
References:
https://docs.microsoft.com/en-us/windows/configuration/configure-windows-10-taskbar

NEW QUESTION: 3
Given the code fragment:
Int [] [] array = {{0}, {0, 1}, {0, 2, 4}, {0, 3, 6, 9}, {0, 4, 8, 12, 16}};
Systemout.printIn(array [4] [1]);
System.out.printIn (array) [1] [4]);
What is the result?
A. Null 4
B. 4 Null
C. An IllegalArgumentException is thrown at run time
D. 4 An ArrayIndexOutOfBoundException is thrown at run time
Answer: D
Explanation:
The first println statement, System.out.println(array [4][1]);, works fine. It selects the element/array with index 4, {0, 4, 8, 12, 16},and from this array it selects the element with index 1, 4. Output: 4 The second println statement, System.out.println(array) [1][4]);, fails. It selects the array/element with index 1, {0, 1}, and from this array it try to select the element with index
4. This causes an exception.
Output: 4 Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4

NEW QUESTION: 4
When simulating a problem on CLusterXL cluster with cphaprob -d STOP -s problem -t 0 register, to initiate a failover on an active cluster member, what command allows you remove the problematic state?
A. cphaprob -d STOP unregister
B. cphaprob STOP unregister
C. cphaprob unregister STOP
D. cphaprob -d unregister STOP
Answer: A
Explanation:
esting a failover in a controlled manner using following command;
# cphaprob -d STOP -s problem -t 0 register
This will register a problem state on the cluster member this was entered on; If you then run;
# cphaprob list
this will show an entry named STOP.
to remove this problematic register run following;
# cphaprob -d STOP unregister
Reference: https://fwknowledge.wordpress.com/2013/04/04/manual-failover-of-the-fw- cluster/

 

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