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NEW QUESTION: 1
NAT types include ( ).
(Select 3 answers)
A. Protocol mapping
B. Static NAT
C. Port mapping
D. Dynamic NAT
Answer: B,C,D
NEW QUESTION: 2
IPv6 OSPFv3接続のどのコンポーネントをIPv4形式で構成する必要がありますか？
A. 主インタフェース
B. 近隣アドレス
C. 二次インタフェース
D. ルータID
Answer: D
NEW QUESTION: 3
Your network contains an Active Directory domain.
A Group Policy object (GRO) named GPO1 is linked to the domain. GPO1 has the settings shown in the following table.
Policy
Policy setting
Enforce password history
5 passwords remembered
Minimum password length
10 characters
You import the backup of a GPO named GPO named GPO2. GPO2 has the settings shown in the following table.
Policy
Policy setting
Minimum password length
5 characters
Store passwords using reversible encryption
Enabled
You import the backup of GPO2 into GPO1.
You need to identify the configurations in GPO1.
What should you identify?
A. Option C
B. Option D
C. Option B
D. Option A
Answer: A
Explanation:
References:
http://www.dell.com/support/article/za/en/zabsdt1/sln283515/windows-server-how-to-import-a- group-policy-objects-settings-into-another-group-policy-object?lang=en
NEW QUESTION: 4
Refer to the exhibit. Customer is planning to deploy a clustering over the WAN UCM topology with 2 subscribers at site 1 and 2 subscribers at site 2.
How much bandwidth would be required between site 1 and site 2 to for database replication?
A. 1.544 Mbps
B. 7.772 Mbps
C. 4.632 Mbps
D. 6.176 Mbps
E. 3.088 Mbps
Answer: C
Explanation:
Consider two sites, Site 1 and Site 2, with Unified CM clustered over the WAN across these two sites that are 80 msec round-trip time apart. Site 1 has one publisher, one combined TFTP and music on hold (MoH) server, and two Unified CM subscriber servers. Site 2 has one TFTP/MoH server and two Unified CM subscriber servers. Site 1 has 5000 phones, each having one DN; and Site 2 has 5000 phones, each having one DN. During the busy hour, 2500 phones in Site 1 call
2500 phones in Site 2, each at 3 BHCA. During that same busy hour, 2500 phones in Site 2 also call 2500 phones in Site 1, each at 3 BHCA. In this case:
Total BHCA during the busy hour = 2500*3 + 2500*3 = 15,000
Total bandwidth required between the sites = Total ICCS bandwidth + Total database bandwidth Because total BHCA is 15,000 (greater than 10,000), we can use the formula to calculate:
Total ICCS bandwidth = (15,000/10,000) * (1 + 0.006*80) = 2.22 Mbps
Total database bandwidth = (Number of servers remote to the publisher) * 1.544 = 3 * 1.544 =
4.632 Mbps
http://www.cisco.com/c/en/us/td/docs/voice_ip_comm/cucm/srnd/7x/uc7_0/models.html
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