JN0-223 Latest Test Answers & Exam JN0-223 Cram - Sample JN0-223 Questions Answers - Cads-Group

  • Exam Number/Code : JN0-223
  • Exam Name : Automation and DevOps, Associate (JNCIA-DevOps)
  • Questions and Answers : 260 Q&As
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
Your network contains an Active Directory domain named adatum.com
You plan to implement Network Access protection (NAP) by using VPN enforcement.
You need to recommend which Windows Server 2012 components must be deployed for the planned implementation.
Which two components should you include in the recommendation?
A. Network Policy Server (NPS)
B. Remote Access Server (RAS)
C. Health Registration Authority (HRA)
D. Host Credential Authorization Protocol (HCAP)
E. Active Directory Rights Management Services (AD RMS)
Answer: A,C

NEW QUESTION: 2
You have an Excel workbook that contains a table named Sales.
You add Sales to the Power Pivot model.
You need to set a column named TransactionID as the row identifier for the Sales table.
What should you do?
A. From Query Editor, modify the Data Type.
B. From Power Pivot, modify the Table Behavior setting.
C. From Power Pivot, modify the Default Field Set.
D. From Query Editor, add an index column.
Answer: B
Explanation:
Explanation
https://msdn.microsoft.com/en-us/library/hh560542(v=sql.110).aspx
* In the Data View of your PowerPivot Window, click the PowerPivot Window: Advanced Tab.
* Click the table tab at the bottom of the window to select the table for which you are configuring properties.
* In Reporting Properties, click Table Behavior.
* Set the Row Identifier, and then proceed to specify other properties in this dialog.
Opening the Table Behavior dialog box
https://ksdconsultancy.blog/2015/10/08/set-table-behaviour-in-powerpivot/

NEW QUESTION: 3
Refer to the exhibit. The internetwork is using subnets of the address 192.168.1.0 with a subnet mask of
255.255.255.224. The routing protocol in use is RIP version 1. Which address could be assigned to the FastEthernet interface on RouterA?

A. 192.168.1.31
B. 192.168.1.127
C. 192.168.1.190
D. 192.168.1.64
E. 192.168.1.192
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Subnet mask 255.255.255.224 with CIDR of /27 which results in 32 hosts per.
192.168.1.31 is the broadcast address for sunbet '0' 192.168.1.64 is the network address for subnet '2'
192.168.1.127 is the broadcast address for subnet '3' 192.168.1.192 is the network address for subnet '6'


 

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