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A. It in Layer 2 trannport-independent
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C. The IP SLA renponder in a component in the nource Cinco device
D. SNMP accenn in not nupported
E. It can meanure MOS
F. It unen active traffic monitoring
Answer: A,F
NEW QUESTION: 2
Before we can come to a decision, we shall need to hear all the pros and cant's of the matter.
A. to hear all the pros and cons of the matter.
B. to hear all the pros to cons of the matter.
C. to hear all the pros of cons of the matter.
D. to hear all the pros the cons of the matter.
E. to hear all the pros and cant's of the matter.
Answer: A
NEW QUESTION: 3
What URL do you use to download a packet capture file in a format which can be used by a packet analyzer?
A. Error! Hyperlink reference not valid.
B. Error! Hyperlink reference not valid.
C. ftp://<hostname>/capture/<capture_name>/
D. Error! Hyperlink reference not valid. _interface:port>/<capture_name>/
Answer: A
NEW QUESTION: 4
You are working for a company that designs mobile applications. They maintain a server where player records are assigned to their different games. The tracking system is new and in development.
The application uses Entity Framework to connect to an Azure Database. The database holds a Player table and Game table.
When adding a player, the code should insert a new player record, and add a relationship between an existing game record and the new player record.
The application will call CreatePlayerWithGame with the correct gameIdand the playerId to start the process. (Line numbers are included for reference only.)
For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation:
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
.HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Post)
.WithMany(p => p.PostTags)
.HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Tag)
.WithMany(t => t.PostTags)
.HasForeignKey(pt => pt.TagId);
}
}
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