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  • Exam Number/Code : H19-391_V1.0
  • Exam Name : HCSP-Presales-Smart PV(Residential) V1.0
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
フォルダーを参照するcsvjolderという名前のファイルデータセットを登録します。フォルダーには、AzureストレージBLOBコンテナー内の複数のコンマ区切り値(CSV)ファイルが含まれています。次のコードを使用して、ファイルデータセットからデータをロードするスクリプトを実行する予定です。次の変数を作成してインスタンス化します。

次のコードがあります。


スクリプトが参照するファイルをスクリプトが確実に読み取れるようにするには、データセットを渡す必要があります。コードコメントを置き換えるには、どのコードセグメントを挿入する必要がありますか?
A)

B)

C)

D)

A. オプションA
B. オプションC
C. オプションD
D. オプションB
Answer: A

NEW QUESTION: 2
DRAG DROP
You have a database that includes the following tables:

You need to create a list of all customer IDs and the date of the last order that each customer placed. If the customer has not placed any orders, you must return the date
January 1, 1900. The column names must be CustomerID and LastOrderDate.
Which four Transact-SQL segments should you use to develop the solution? To answer, move the appropriate Transact-SQL segments from the list of Transact-SQL segments to the answer area and arrange them in the correct order.

Answer:
Explanation:

Explanation:

Box 1: SELECT..COALESCE...
The COALESCE function evaluates the arguments in order and returns the current value of the first expression that initially does not evaluate to NULL.
Box 2: ..LEFT OUTER JOIN..
The LEFT JOIN (LEFT OUTER JOIN) keyword returns all rows from the left table (table1), with the matching rows in the right table (table2). The result is NULL in the right side when there is no match. A customer might have no orders so the right table must be allowed have a NULL value.
Box 3: ON c.custid = o.custid
We JOIN on the custID column, which is available in both tables.
Box 4: GROUP BY c.custid
References:
https://technet.microsoft.com/en-us/library/ms189499(v=sql.110).aspx
http://www.w3schools.com/sql/sql_join_left.asp

NEW QUESTION: 3
SIMULATION
The abbreviation ac means
Answer:
Explanation:
Before meals

 

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Cert H19-391_V1.0 Exam | Huawei H19-391_V1.0 Certification Materials & H19-391_V1.0 Reliable Exam Review - Cads-Group


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