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NEW QUESTION: 1
Drag and drop the QoS congestion management terms from the left onto the description on the right.

Answer:
Explanation:

NEW QUESTION: 2
HOTSPOT
You are creating a function by using JavaScript. The function accepts an object as the parameter and returns a string that identifies the data type of the object.
You have the following requirements:
The function must return "Number" if the object is a number.
The function must return "String" if the object is a string.
The function must return "Unknown" if the object is neither a number nor a string.
You need to implement the function to meet the requirements.
How should you build the code segment? (To answer, select the appropriate options from the drop- down lists in the answer area.)


Answer:
Explanation:

* Use the switch statement to select one of many blocks of code to be executed.
Syntax
switch(expression) {
case n:
code block
break;
case n:
code block
break;
default:
default code block
}
This is how it works:
The switch expression is evaluated once.
The value of the expression is compared with the values of each case.
If there is a match, the associated block of code is executed.
* Object.prototype.constructor
Returns a reference to the Object function that created the instance's prototype. Note that the value of this property is a reference to the function itself, not a string containing the function's name. The value is only read-only for primitive values such as 1, true and "test".
* Description
All objects inherit a constructor property from their prototype:
var o = {};
o.constructor === Object; // true
var a = [];
a.constructor === Array; // true
var n = new Number(3);
n.constructor === Number; // true
* The constructor property is created together with the function as a single property of func.prototype.
Reference: JavaScript Switch Statement;Object.prototype.constructor

NEW QUESTION: 3
タンブリングウィンドウの正しい定義は何ですか？正しい答えを選びなさい：
A. ウィンドウ化照会が各ウィンドウを重複しない方法で処理する場合、アプリケーション内ストリーム上の各レコードは特定のウィンドウに属し、そのレコードは1回しか処理されません（照会がレコードが属するウィンドウを処理する場合） 。
B. 上記のどれでもない
C. ウィンドウ化照会が各ウィンドウを重複しない方法で処理する場合、アプリケーション内ストリーム上の各レコードは任意のウィンドウに属し、そのレコードは1回しか処理されません（照会がレコードが属するウィンドウを処理する場合）。
D. ウィンドウクエリが各ウィンドウを重複して処理する場合、アプリケーション内ストリームの各レコードは特定のウィンドウに属し、そのレコードは1回だけ処理されます（レコードが属するウィンドウがクエリによって処理される場合）。
Answer: A
Explanation:
When a windowed query processes each window in a non-overlapping manner, the window is referred to as a tumbling window. In this case, each record on an in-application stream belongs to a specific window, and its processed only once (when the query processes the window to which the record belongs).
Reference:
http://docs.aws.amazon.com/kinesisanalytics/latest/dev/tumbling-window-concepts.html

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