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  • Exam Number/Code : FCSS_SDW_AR-7.4
  • Exam Name : FCSS - SD-WAN 7.4 Architect
  • Questions and Answers : 260 Q&As
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
You have an Azure subscription named Subscription1. Subscription1 contains the resources in the following table:

VNet1 is in RG1. VNet2 is in RG2. There is no connectivity between VNet1 and VNet2. An administrator named Admin1 creates an Azure virtual machine VM1 in RG1. VM1 uses a disk named Disk1 and connects to VNet1. Admin1 then installs a custom application in VM1.
You need to move the custom application to VNet2. The solution must minimize administrative effort.
Which two actions should you perform? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation


NEW QUESTION: 2
A Chief Executive Officer (CEO) is giving a presentation at an industry conference but forgot to bring a laptop. The company has emailed several large presentation files and the links to several videos that will be streamed during the presentation. While showing the last video, it starts to buffer, times out. and will not display The CEO restarts the phone that is being used for the presentation and verifies there is enough free storage space, but the video still will not play Which of the following is MOST likely causing the Issue?
A. Unauthorized account access
B. Unintended Bluetooth pairing
C. Data transmission over limit
D. Resource over use
Answer: C

NEW QUESTION: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.0.0.0.1
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.0.255.255.255.254
D. Permit 10.0.0.1.0.0.0.0
Answer: B
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 000 ) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.

NEW QUESTION: 4
Universal Containers (UC) owns a complex Salesforce org with many Apex classes, triggers, and automated processes that will modify records if available. UC has identified that, in its current development state, UC runs change of encountering race condition on the same record.
What should a data architect recommend to guarantee that records are not being updated at the same time?
A. Embed the keywords FOR UPDATE after SOQL statements.
B. Refactor or optimize classes and trigger for maximum CPU performance.
C. Disable classes or triggers that have the potential to obtain the same record.
D. Migrate programmatic logic to processes and flows.
Answer: A

 

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