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  • Exam Number/Code : FCSS_LED_AR-7.6
  • Exam Name : FCSS - LAN Edge 7.6 Architect
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
Jorgensen Products has just issued 25,000,000 in 4.50% annual coupon bonds at a market yield of
4 .80%. The bonds have a maturity of 8 years. What adjustments would an analyst make to the CFF at the end of the first year?
A. Decrease by 488,681
B. Decrease by 51,543
C. Increase by 51,543
Answer: C
Explanation:
Proceeds of bond issue: PMT = 1,125,000; I/Y = 4.80; FV = 25,000,000; N = 8; CPT PV =
2 4,511,316 Jorgensen will recognize this as a liability. Its annual interest will be, interest = 0.048 x
2 4,511,316 = 1,176,543 Jorgensen records a CFO of -1,125,000 based on the coupon payment. The analyst would reduce the CFO by 51,543 to reflect the higher interest cost (= 1,176,543 - 1,125,000).The
CFF would have to be increased by the same amount, 51,543, to reflect the fact that this differential interest is owed and will be paid at maturity. Thus, CFF will have to be increased by 51,543.

NEW QUESTION: 2
솔루션 아키텍트가 회사의 예정된 야간 유지 관리 비용을 검토하고 있습니다. 솔루션 아키텍트는 3 개의 Amazon EC2 인스턴스가 실행되어 각각 완료하는 데 5 분도 채 걸리지 않는 9 개의 스크립팅 작업을 수행하고 있음을 확인합니다. 스크립트는 모두 Python으로 작성되었습니다. 회사는 야간 유지 보수 비용을 최적화하기 위해 어떤 조치를 취해야합니까?
A. 실행중인 EC2 인스턴스에 대한 컴퓨팅 절약 계획을 구매합니다.
B. 스크립트 실행을 위해 실행중인 EC2 인스턴스를 대체 할 스팟 집합을 생성합니다.
C. 하나의 EC2 인스턴스에서 실행되도록 3 개의 EC2 인스턴스의 스크립트를 통합합니다.
D. 스크립트를 AWS Lambda 함수로 변환하고 Amazon EventBridge (Amazon CloudWatch Events)를 사용하여 예약합니다.
Answer: D

NEW QUESTION: 3
You use a Microsoft Azure SQL Database instance named ContosoDb. ContosoDb contains a table named Customers that has existing records.
The Customers table has columns named Id and Name.
You need to create a new column in the Customer table named Status that allows null values and sets the value of the Status column to Silver for all existing records.
Which three Transact-SQL segments should you use to develop the solution? To answer, move the appropriate Transact-SQL segments from the list of Transact-SQL segments to the anwer area and arrange them in the correct order.

Answer:
Explanation:

Explanation

NULL or NOT NULL specifies whether the column can accept null values. Columns that do not allow null values can be added with ALTER TABLE only if they have a default specified or if the table is empty. NOT NULL can be specified for computed columns only if PERSISTED is also specified. If the new column allows null values and no default is specified, the new column contains a null value for each row in the table. If the new column allows null values and a default definition is added with the new column, WITH VALUES can be used to store the default value in the new column for each existing row in the table.
References:
https://docs.microsoft.com/en-us/sql/t-sql/statements/alter-table-transact-sql?view=sql-server-2017

 

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Let FCSS_LED_AR-7.6 Practice Exams Free Help You Pass The FCSS - LAN Edge 7.6 Architect - Cads-Group


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