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NEW QUESTION: 1
A user has a laptop named Computer 1 that runs Windows 10 and has a 64-bit application named App1 installed.
App1 fails to launch and generates an error message indicating that the application is not supported on this version of Windows.
You need to ensure that App1 can run successfully.
What should you do?
A. Use the Application Compatibility Manager (ACM) to create aninventory package.
B. Run App1 in the Standard User Analyzer (SUA).
C. Create a fix in the Compatibility Administrator.
D. Create a package that includes App1 by using the Windows Imaging and Configuration
Designer (Windows ICD).
Answer: C
Explanation:
https://msdn.microsoft.com/en-us/library/windows/desktop/dd744763(v=vs.85).aspx
NEW QUESTION: 2
Sie haben einen Microsoft Azure Active Directory-Mandanten mit dem Namen contoso.com.
Ein Benutzer mit dem Namen Benutzer1 verfügt über Dateien auf einem Windows 10-Gerät (siehe folgende Tabelle).
In Azure Information Protection erstellen Sie eine Bezeichnung mit dem Namen Label1, die für die automatische Anwendung konfiguriert ist.
Label1 ist wie in der folgenden Abbildung gezeigt konfiguriert.
Wählen Sie für jede der folgenden Anweisungen Ja aus, wenn die Anweisung wahr ist. Andernfalls wählen Sie Nein.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.
Answer:
Explanation:
Explanation:
The phrase to match is "im" and it is case sensitive. The phrase must also appear at least twice.
Box 1: No
File1.docx contain the word "import" once only
Box 2: Yes
File2.docx contains two occurrences of the word "import" as well as the word "imported" Box 3: No File3.docx contains "IM" but his is not the correct letter case.
References:
https://docs.microsoft.com/en-us/azure/information-protection/configure-policy-classification
NEW QUESTION: 3
展示を参照してください。
60ホストとの新しいサブネットをネットワークに追加されました。最も少ないのアドレスを無駄にしながら、このネットワークの使用は、十分な使用可能なアドレスを提供する必要があるサブネットアドレスはどれですか？
A. 192.168.1.64/27
B. 192.168.1.64/26
C. 192.168.1.56/27
D. 192.168.1.56/26
Answer: B
Explanation:
A subnet with 60 host is 2*2*2*2*2*2 = 64 -2 == 62
6 bits needed for hosts part. Therefore subnet bits are 2 bits (8-6) in fourth octet.
8bits+ 8bits+ 8bits + 2bits = /26
/26 bits subnet is 24bits + 11000000 = 24bits + 192
256 - 192 = 64
0 -63
64 - 127
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