Advanced FCSS_ADA_AR-6.7 Testing Engine | FCSS_ADA_AR-6.7 Reliable Exam Papers & FCSS_ADA_AR-6.7 Valid Exam Materials - Cads-Group

  • Exam Number/Code : FCSS_ADA_AR-6.7
  • Exam Name : FCSS—Advanced Analytics 6.7 Architect
  • Questions and Answers : 260 Q&As
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
You need to create a Seminar Statistics page that shows a decimal field by using SumlndexField Technology (SIFT).
Which calculation of the CalcFormula method should you use?
A. LOCKUP
B. EXIST
C. SUM
D. COUNT
Answer: C

NEW QUESTION: 2
AzureBlobストレージを使用するアプリケーションがあります。
BLOBのメタデータを更新する必要があります。
ソリューションを開発するために使用する必要がある3つの方法はどれですか?回答するには、適切なメソッドをメソッドのリストから回答領域に移動し、正しい順序で配置します。

Answer:
Explanation:

Explanation

Metadata.Add example:
// Add metadata to the dictionary by calling the Add method
metadata.Add("docType", "textDocuments");
SetMetadataAsync example:
// Set the blob's metadata.
await blob.SetMetadataAsync(metadata);
// Set the blob's properties.
await blob.SetPropertiesAsync();
Reference:
https://docs.microsoft.com/en-us/azure/storage/blobs/storage-blob-properties-metadata

NEW QUESTION: 3
Sie entwickeln eine Azure Cosmos DB-Lösung mithilfe der Azure Cosmos DB-SQL-API. Die Daten umfassen Millionen von Dokumenten. Jedes Dokument kann Hunderte von Eigenschaften enthalten.
Die Eigenschaften der Dokumente enthalten keine eindeutigen Werte für die Partitionierung. Azure Cosmos DB muss einzelne Container in der Datenbank skalieren, um die Leistungsanforderungen der Anwendung zu erfüllen, indem die Arbeitslast im Laufe der Zeit gleichmäßig auf alle Partitionen verteilt wird.
Sie müssen einen Partitionsschlüssel auswählen.
Welche zwei Partitionsschlüssel können Sie verwenden? Jede richtige Antwort bietet eine vollständige Lösung.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.
A. Ein Wert, der den Sammlungsnamen enthält
B. Eine Verkettung mehrerer Eigenschaftswerte mit einem angehängten zufälligen Suffix
C. Ein einzelner Eigenschaftswert, der in den Dokumenten häufig vorkommt
D. ein einzelner Eigenschaftswert, der in den Dokumenten nicht häufig vorkommt
E. Ein Hash-Suffix, das an einen Eigenschaftswert angehängt wird
Answer: B,E
Explanation:
Erläuterung:
Sie können einen Partitionsschlüssel bilden, indem Sie mehrere Eigenschaftswerte in einer einzelnen künstlichen partitionKey-Eigenschaft verketten. Diese Schlüssel werden als synthetische Schlüssel bezeichnet.
Eine andere mögliche Strategie, um die Arbeitslast gleichmäßiger zu verteilen, besteht darin, am Ende des Partitionsschlüsselwerts eine Zufallszahl anzufügen. Wenn Sie Elemente auf diese Weise verteilen, können Sie parallele Schreibvorgänge über Partitionen ausführen.
Hinweis: Es wird empfohlen, einen Partitionsschlüssel mit vielen unterschiedlichen Werten wie z. B. Hunderten oder Tausenden zu verwenden. Ziel ist es, Ihre Daten und Arbeitslast gleichmäßig auf die Elemente zu verteilen, die diesen Partitionsschlüsselwerten zugeordnet sind. Wenn eine solche Eigenschaft in Ihren Daten nicht vorhanden ist, können Sie einen synthetischen Partitionsschlüssel erstellen.
Verweise:
https://docs.microsoft.com/en-us/azure/cosmos-db/synthetic-partition-keys

NEW QUESTION: 4

ONE
NUM VAR
1 A
2 B
3 C

A. proc sql;
Drop table one;
Quit;
B. proc sql;
Delete from one;
Quit;
C. proc sql;
Remove table one;
Quit;
D. proc sql;
Delete table one;
Quit;
Answer: A

 

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