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NEW QUESTION: 1
Refer to the exhibit.
While troubleshooting a switch, you executed the show interface port-channel 1 etherchannel command and it returned this output. Which information is provided by the Load value?
A. the preference of the link
B. the session count of the link
C. the number source-destination pairs on the link
D. the percentage of use of the link
Answer: C
NEW QUESTION: 2
Which of the following Linux commands can be used to set an expiration date for a user's password?
A. chmod
B. chage
C. chown
D. chgrp
Answer: B
NEW QUESTION: 3
DRAG DROP
Answer:
Explanation:
NEW QUESTION: 4
注：この質問は、同じまたは類似の回答の選択肢を使用する一連の質問の一部です。 回答の選択肢は、シリーズの複数の質問に対して正しいかもしれません。 各質問は、このシリーズの他の質問とは独立しています。 質問に記載されている情報や詳細がその質問に適用されます。
あなたには、銀行システム用のデータベースがあります。 データベースには、預金口座とローン口座をそれぞれ格納する2つのテーブルtblDepositAcctとtblLoanAcctがあります。 どちらの表にも次の列があります。
ローンアカウントのみを持つ顧客の総数を決定する必要があります。
どのTransact-SQL文を実行する必要がありますか？
A. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
H. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
I. CustNoWHERE D.CustNo IS NULL
Answer: E
Explanation:
Explanation
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp
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