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NEW QUESTION: 1
Your customer uses classic G/L and asks for possibilities to implement new functionalities. What functionality can be activated during the conversion? Please choose the correct answer.
A. Document splitting
B. Additional FI currency
C. Transfer prices
D. Account-based CO-PA
Answer: D

NEW QUESTION: 2
You have a Microsoft 365 subscription that uses a default domain named contoso.com.
Users report that email messages from a domain named fabrikam.com are identified as spam even through the messages are legitimate.
You need to prevent messages from fabrikam.com from being identified as spam.
What should you do?
A. Create a new malware filter policy.
B. Edit the default mail flow rule to bypass the spam filter.
C. Modify the IP Allow list of a connection filter policy.
D. Create a new remote domain.
Answer: C

NEW QUESTION: 3
View the Exhibit.

You are designing an IP addressing scheme for the network in the exhibit above.
Each switch represents hosts that reside in separate VLANs. The subnets should be allocated to match the following host capacities:
Router subnet: two hosts

SwitchA subnet: four hosts

SwitchB subnet: 10 hosts

SwitchC subnet: 20 hosts

SwitchD subnet: 50 hosts

You have chosen to subnet the 192.168.51.0/24 network.
Which of the following are you least likely to allocate?
A. a /27 subnet
B. a /25 subnet
C. a /30 subnet
D. a /29 subnet
E. a /26 subnet
F. a /28 subnet
Answer: B
Explanation:
Explanation/Reference:
Section: Addressing and Routing Protocols in an Existing Network Explanation Explanation:
Of the available choices, you are least likely to allocate a /25 subnet. The largest broadcast domain in this scenario contains 50 hosts. A /25 subnet can contain up to 126 assignable hosts. In this scenario, allocating a /25 subnet would reserve half the 192.168.51.0/24 network for a single virtual LAN (VLAN).
The total number of hosts for which you need addresses in this scenario is 86. Therefore, you would only need to use half the /24 subnet if all 86 hosts were residing in the same VLAN.
You should begin allocating address ranges starting with the largest group of hosts to ensure that the entire group has a large, contiguous address range available. Subnetting a contiguous address range in structured, hierarchical fashion enables routers to maintain smaller routing tables and eases administrative burden when troubleshooting.
You are likely to use a /26 subnet. In this scenario, the largest VLAN contains 50 hosts. If you were to divide the 192.168.51.0/25 subnet into two /26 subnets, the result would be two new subnets capable of supporting up to 62 assignable hosts: the 192.168.51.0/26 subnet and the 192.168.51.64/26 subnet.
Therefore, you should start subnetting with a /26 network. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.64/26 subnet to SwitchD's VLAN.
You are likely to use a /27 subnet. The nextlargest broadcast domain in this scenario is the SwitchC subnet, which contains 20 hosts. If you were to divide the 192.168.51.0/26 subnet into two /27 subnets, the result would be two new subnets capable of supporting up to 30 assignable hosts: the 192.168.51.0/27 subnet and the 192.168.51.32/27 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.32/27 subnet to SwitchC's VLAN.
You are likely to use a /28 subnet. The nextlargest broadcast domain in this scenario is the SwitchB subnet, which contains 10 hosts. If you were to divide the 192.168.51.0/27 subnet into two /28 subnets, the result would be two new subnets capable of supporting up to 14 assignable hosts: the 192.168.51.0/28 subnet and the 192.168.51.16/28 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.16/28 subnet to SwitchB's VLAN.
You are likely to use a /29 subnet. The nextlargest broadcast domain in this scenario is the SwitchA subnet, which contains four hosts. If you were to divide the 192.168.51.0/28 subnet into two /29 subnets, the result would be two new subnets capable of supporting up to six assignable hosts: the 192.168.51.0/29 subnet and the 192.168.51.8 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.8/29 subnet to SwitchA's VLAN.
You are likely to use a /30 subnet. The final subnet in this scenario is the link between RouterA and RouterB, which contains two hosts. If you were to divide the 192.168.51.0/29 subnet into two /30 subnets, the result would be two new subnets capable of supporting two assignable hosts each: the
192.168.51.0/30 subnet and the 192.168.51.4/30 subnet. To maintain a logical, hierarchical IP structure, you could then allocate the 192.168.51.4/30 subnet to the link between RouterA and RouterB. This would leave the 192.168.51.0/30 subnet unallocated. However, you could further divide the 192.168.51.0/30 subnet into single /32 host addresses that could then be used for loopback IP addressing on the routers.
Reference:
CCDA 200-310 Official Cert Guide, Chapter 8, IPv4 Address Subnets, pp. 302-310 CCDA 200-310 Official Cert Guide, Chapter 8, Plan for a Hierarchical IP Address Network, pp. 311-312 Cisco: IP Addressing and Subnetting for New Users

NEW QUESTION: 4
Identify the option that contains the components required for setting up advanced preference processing.
A. Sales Order Entry processing options, Branch/Plant Constants, Preference Details, and Hierarchy
B. Adjustment Definitions, Hierarchy, Branch/Plant Constants, and Preference Details
C. Sales Order Entry processing options, Order Activity Rules, System Constants, and Preference Master
D. Hierarchy, Preference Master, System Constants, and Schedules
E. Preference Schedules, Preference Details, System Constants, and Sales Order Entry processing options
Answer: E
Explanation:
Explanation/Reference:
Reference: https://docs.oracle.com/cd/E16582_01/doc.91/e15146/
activate_preferences.htm#EOASO01044

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