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  • Exam Number/Code : Accident-and-Health-or-Sickness-Producer
  • Exam Name : MarylandAccident and Health or Sickness Producer Series 20-24 Exam
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NEW QUESTION: 1
You are performing an upgrade with SUM. You are in the BIND_PATCH phase of the roadmap step
"Configuration". For some software components you find entries in the "Calculated level" column.
What does the "Calculated level" indicate for those software components?
Please choose the correct answer.
Response:
A. The SAP Support Packages contained in the upgrade media
B. The SAP Support Packages that will be bound to the upgrade
C. The SAP Support packages of the Support Package Stack, calculated by the Maintenance Planner
D. The SAP Support Packages found in the download directory
Answer: D

NEW QUESTION: 2
In which two ways should companies modernize their security philosophies? (Choose two.)
A. Expand their IT departments.
B. Reinforce their threat-centric security tactics.
C. Complement threat-centric tactics with trust-centric methods.
D. Rebuild their security portfolios with new solutions
E. Decrease internal access and reporting
Answer: B,D

NEW QUESTION: 3
Layer 4 application mapping allows which of the following criteria to match an application:
(Select 3)
A. IP protocol
B. Port number
C. User name
D. IP address of the host
E. MAC address of the host
F. Application name
Answer: A,B,D

NEW QUESTION: 4
Sie erstellen eine Tabelle mit den Spalten StudentCode, SubjectCode und Marks, um die Halbjahresnoten für die Schüler aufzuzeichnen. Die Tabelle enthält Noten von 50 Schülern für verschiedene Fächer.
Sie müssen sicherstellen, dass die folgenden Anforderungen erfüllt sind:
* Die Einstufung der Schüler muss anhand ihrer Durchschnittsnote erfolgen.
* Wenn ein oder mehrere Schüler den gleichen Durchschnitt haben, müssen diese Schüler den gleichen Rang erhalten.
* Aufeinanderfolgende Ränge müssen übersprungen werden, wenn derselbe Rang zugewiesen wird.
Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks DESC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
B. SELECT StudentCode as Code,
NTILE (2) OVER (BESTELLUNG NACH AVG (Marks) DESC) AS-Wert
VON StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode as Code,
RANG () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
DENSE_RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY ASC-Zeichen) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
F. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Markiert ASC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
G. SELECT ID, Name, Markierungen,
DENSE_RANK () ÜBER (ORDER BY Markiert DESC) ALS Rang
VON StudentMarks
H. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) ALS Rang
FROM StudentMarks) tmp
WO Rang = 1
Answer: C
Explanation:
Reference:
http://msdn.microsoft.com/en-us/library/ms189798.aspx

 

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