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  • Exam Number/Code : 2V0-71.23
  • Exam Name : VMware Tanzu for Kubernetes Operations Professional
  • Questions and Answers : 260 Q&As
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
次の展示をご覧ください。

この失敗したインストールログに関して正しい説明はどれですか。
A. ポリシーID2はインストールされません
B. ポリシーID2がソースデバイスなしでインストールされている
C. ポリシーID2が送信元アドレスなしでインストールされている
D. ポリシーID2が無効な状態でインストールされている
Answer: B

NEW QUESTION: 2
DRAG DROP
What is the correct priority list that Solutions Enabler will use to select a device for use as a Gatekeeper (GK)?

Answer:
Explanation:

Explanation:
Step 1 - Small (< 10 cylinders) with inguiry GK flag
Step 2 - Standard non-RDF and non-metadevices
Step 3 - R1 devices
Step 4 - R2 devices
Step 5 - VCM/ACLX devices
Solutions Enabler selects a gatekeeper from the candidate list based on a preestablished priority scheme. The gatekeeper priority list includes all gatekeeper candidates prioritized from the highest to the lowest, as shown below:
1. Small (< 10 cylinders) devices, marked by the Symmetrix array with the inquiry gatekeeper flag.
2. Standard non-RDF and non-metadevices.
3. RDF R1 devices.
4. RDF R2 devices.
5. VCM/ACLX devices.

NEW QUESTION: 3



A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
C. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
D. CustNo
E. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
F. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
G. CustNoWHERE D.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
J. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
Answer: B
Explanation:
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp

NEW QUESTION: 4

Answer:
Explanation:


 

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