Latest 250-580 Exam Practice - Symantec Advanced 250-580 Testing Engine, 250-580 Valid Practice Materials - Cads-Group

  • Exam Number/Code : 250-580
  • Exam Name : Endpoint Security Complete - Administration R2
  • Questions and Answers : 260 Q&As
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
Linda works as a Database Designer for Lion Inc. She has been given an assignment to design the database of a publishing company. The database has a table named Author, which has a composite key, AuthorID and TitleID. Royalty and LiteraryAgent are the other attributes. The functional dependencies are such that AuthorID + TitleID-> Royalty (i.e. Royalty is functionally dependent on AuthorID and TitleID) and AuthorID-> LiteraryAgent
(i.e.
LiteraryAgent is functionally dependent on AuthorID). Which of the following is true about this table?
A. There is no violation.
B. It violates 1NF.
C. It violates 2NF.
D. It violates 4NF.
Answer: C
Explanation:
It violates the 2NF. According to 2NF, all the attributes that are not part of the primary key should be functionally dependent on the entire key attributes (composite key). Here, Literary Agent is functionally dependent on one of the composite key attributes, i.e. AuthorID. To make this in 2NF, the Author table should be decomposed into two tables such that the first table contains AuthorID, TitleID, and Royalty as its attributes, and the second table contains AuthorID and LiteraryAgent as its attributes. This will make the two tables in 2NF.

NEW QUESTION: 2

A. 0
B. 1
C. 2
D. 3
Answer: B

NEW QUESTION: 3
어떤 서비스가 AWS 클라우드를 포함하는 하이브리드 아키텍처에서 네트워크 연결을 제공합니까?
A. Amazon VPC
B. AWS 디렉토리 서비스
C. Amazon API 게이트웨이
D. AWS Direct Connect
Answer: A
Explanation:
Amazon Virtual Private Cloud (Amazon VPC) is a logically isolated, private section of the AWS Cloud to launch resources in a virtual data center in the cloud. Amazon VPC allows you to leverage multiple Availability Zones (AZ) within a region so that you can build greater fault tolerance within your workloads. You have complete control.
Reference:
https://aws.amazon.com/blogs/publicsector/aws-networking-capabilities-gives-you-choices-for-hybrid-cloud-connectivity-but-which-service-works-best-for-your-use-case/

NEW QUESTION: 4
Sie verwalten eine Microsoft SQL Server 2012-Datenbank, die eine Tabelle mit dem Namen Produkte enthält. Die Products-Tabelle enthält Spalten mit den Namen ProductId, ProductName und CreatedDateTime.
Die Tabelle enthält eine eindeutige Einschränkung für die Kombination von ProductName und CreatedDateTime.
Sie müssen die Produkttabelle ändern, um die folgenden Anforderungen zu erfüllen:
* Entfernen Sie alle Duplikate der Tabelle "Produkte" basierend auf der Spalte "Produktname".
* Behalten Sie nur die neueste Produktzeile bei.
Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. MIT CTEDupRecords
WIE
(
SELECT MAX (CreatedDateTime) AS CreatedDateTime, ProductName
VON Produkten
GRUPPE NACH Produktname
COUNT HABEN (*)> 1
)
LÖSCHEN p
VON Produkten p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
UND p.CreatedDateTime> cte.CreatedDateTime
B. MIT CTEDupRecords
WIE
(
SELECT MIN (CreatedDateTime) AS CreatedDateTime, ProductName
VON Produkten
GRUPPE NACH Produktname
)
LÖSCHEN p
VON Produkten p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
C. MIT CTEDupRecords
WIE
(
SELECT MAX (CreatedDateTime) AS CreatedDateTime, ProductName
VON Produkten
GRUPPE NACH Produktname
COUNT HABEN (*)> 1
)
LÖSCHEN p
VON Produkten p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
D. MIT CTEDupRecords
WIE
(
SELECT MAX (CreatedDateTime) AS CreatedDateTime, ProductName
VON Produkten
GRUPPE NACH Produktname
COUNT HABEN (*)> 1
)
LÖSCHEN p
VON Produkten p
JOIN CTEDupRecords cte ON
cte.ProductName = p.ProductName
AND cte.CreatedDateTime> p.CreatedDateTime
Answer: D

 

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Latest 250-580 Exam Practice - Symantec Advanced 250-580 Testing Engine, 250-580 Valid Practice Materials - Cads-Group


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