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  • Exam Number/Code : 1z1-829
  • Exam Name : Java SE 17 Developer
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
顧客が本番ポータルアプリケーションをAWSにデプロイしています。データベース層には構造化データがあります。会社には、管理が容易で可用性の高いソリューションが必要です。
これらの要件をどのように満たすことができますか?
A. 複数のアベイラビリティーゾーンにわたってAmazon EBSが支援する複数のAmazon EC2インスタンスにデータベースをデプロイします。
B. Amazon DynamoDBを使用します。
C. 単一のアベイラビリティーゾーンオプションでRDSを使用し、定期的なデータベーススナップショットをスケジュールします。
D. 複数のアベイラビリティーゾーンオプションでAmazon RDSを使用します。
Answer: D
Explanation:
Explanation
https://aws.amazon.com/rds/

NEW QUESTION: 2
In a Kerberos exchange involving a message with an authenticator, the
authenticator contains the client ID and which of the following?
A. Timestamp
B. Client network address
C. Client/TGS session key
D. Ticket Granting Ticket (TGT)
Answer: A
Explanation:
A timestamp, t, is used to check the validity of the accompanying request since a Kerberos ticket is valid for some time window, v, after it is issued. The timestamp indicates when the ticket was issued.
*The TGT, is comprised of the client ID, the client network address, the starting and ending time the ticket is valid (v), and the client/TGS session key. This ticket is used by the client to request the service of a resource on the network from the TGS.
*The client/TGS session key, Kc, tgs, is the symmetric key used for encrypted communication between the client and TGS for this particular session.
*the client network address is included in the TGT and not in the authenticator.

NEW QUESTION: 3
You have assign an office 365 plan to users that do not require a full Office client, but do support hosted voicemail.
What is the least cost plan you must assign?
A. Office 365 Medium Business
B. Office 365 Enterprise E1
C. Office 365 Enterprise E3
D. Office 365 Enterprise E4
Answer: C
Explanation:
References: https://products.office.com/en-za/business/office-365-enterprise-e3-business-software

NEW QUESTION: 4
To interact with a ServiceNow instance a ______ role for the MID Server's user account is required.
Response:
A. discovery_adm
B. mid_server_discovery_admin
C. mid_server
D. sm_mid_admin
Answer: C

 

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