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  • Exam Number/Code : 1Z0-1078-23
  • Exam Name : Oracle Product Lifecycle Management 2023 Implementation Professional
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
停止を防ぐために無効にする必要がある証明書の有効期限オプションは何ですか?
A. 有効期限が切れる証明書と署名者を削除します。
B. 有効期限が切れる自己署名証明書を自動的に置き換えます。
C. チェックを有効にします。
D. 有効期限チェック通知を有効にします。
Answer: B
Explanation:
実稼働環境でWebSphere Application Serverが有効期限切れの証明書を自動的に置換できるようにすると、短期または長期の停止を引き起こす可能性があります

NEW QUESTION: 2
How can an IBM Garage Method Reference Architecture help break down the solution to a business
problem?
A. It identifies the different IaaS, PaaS and SaaS services that must be used to create different parts of
the solution.
B. It identifies the low level system modules required to meet the business defined requirements.
C. It identifies the DevOps tooling that is required to ensure the solution runs in production.
D. It identifies the different personas that need to take charge of different aspects of the solution.
Answer: B

NEW QUESTION: 3
The following descriptions about the features of OpenStack are correct: (multiple choice)
A. OpenStack allocates resources in the resource pool to different tenants according to the needs of users to carry different applications
B. OpenStack requires a third-party system to provide fault location and troubleshooting capabilities
C. OpenStack provides a man-machine interface. The outside world can communicate with OpenStack through API, command line or graphical interface.
Line interaction
D. Through its own virtualization functions and software-defined methods, OpenStack abstracts various hardware resources into resource pools
Answer: A,C

NEW QUESTION: 4

A. 192.168.4.67
B. 192.168.4.132
C. 192.168.4.63
D. 192.168.4.61
E. 192.168.4.128
F. 192.168.4.125
Answer: A,F
Explanation:
Explanation
Increment: 64 (/26 = 11111111.11111111.11111111.11000000)
The IP 192.168.4.0 belongs to class C.
The default subnet mask of class C is /24 and it has been subnetted with a /26 mask so we have 2(26-24) = 22 = 4 sub-networks:
1st subnet: 192.168.4.0 (to 192.168.4.63)
2nd subnet: 192.168.4.64 (to 192.168.4.127)
3rd subnet: 192.168.4.128 (to 192.168.4.191)
4th subnet: 192.168.4.192 (to 192.168.4.225)
In all the answers above, only answer C and D are in the same subnet.
Therefore only IPs in this range can be assigned to hosts.

 

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Exam 1Z0-1078-23 Fees & 1Z0-1078-23 Visual Cert Test - 1Z0-1078-23 Dumps Collection - Cads-Group


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